miskahn Posted August 8, 2011 Report Share Posted August 8, 2011 when a weapon says that it is 9d5 (average 24) or what ever that isn't an exact amount of a weapon just guessing here lol what does that all really mean? :confused: :confused: Link to comment Share on other sites More sharing options...
Twinblades713 Posted August 8, 2011 Report Share Posted August 8, 2011 It means when calculating damage, it rolls 9 five-sided dice. That means if you roll those, you have the capability of getting all ones, all fives, or anything in between. If you roll 9 ones, you would do 9 damage. If you roll 9 fives, you would do 45 damage. The average- 9+45 = 54/2 = 27. I could be wrong in there, but I would say the average of that item would be 27. D: Someone wanna check my stats there? Unless you looked at that with a lore, then it has the possibility of being inaccurate. Link to comment Share on other sites More sharing options...
jibber Posted August 8, 2011 Report Share Posted August 8, 2011 Average is actually 24, as it's stated. Link to comment Share on other sites More sharing options...
Twinblades713 Posted August 8, 2011 Report Share Posted August 8, 2011 How? Link to comment Share on other sites More sharing options...
jibber Posted August 8, 2011 Report Share Posted August 8, 2011 My bad. It's 27. Not sure why he put average 24... but the formula is: a + (a * b - a) / 2 = x So.. 9 + (9 * 5 - 9) / 2 9*5 = 45, -9 = 36 / 2 = 18 + 9 = 27. Link to comment Share on other sites More sharing options...
f0xx Posted August 8, 2011 Report Share Posted August 8, 2011 =ROUNDDOWN(((a*b)/2)+(a/2); 0) = (45/2)+(9/2) = 22.5+4.5 = 27 Lol, we all have different formulas. PS. The AVG is 27 indeed, MAX is 45, MIN is 9 Link to comment Share on other sites More sharing options...
miskahn Posted August 8, 2011 Author Report Share Posted August 8, 2011 when a weapon says that it is 9d5 (average 24) or what ever that isn't an exact amount of a weapon just guessing here lol what does that all really mean? :confused: :confused: read it again i said this isn't an exact amount of a weapon just guessing here Link to comment Share on other sites More sharing options...
f0xx Posted August 8, 2011 Report Share Posted August 8, 2011 Developping Jibber's formula will eventually lead to my own: a+(a*b-a)/2 = = a+(a*b)/2-a/2= =(2a-a)/2+(a*b)2= =a/2+(a*b)/2 or (a*b)/2+(a/2) Link to comment Share on other sites More sharing options...
Imoutgoodbye Posted August 8, 2011 Report Share Posted August 8, 2011 And I'm the one who needs help with Algebra? Yeesh! Link to comment Share on other sites More sharing options...
P_body Posted August 9, 2011 Report Share Posted August 9, 2011 That's all fine and dandy, by what does that mean in ok? Does that mean each hit will take away an avg of 27hp? I've never played D&D or anything like that so I'm just trying to figure out what's going on here. Link to comment Share on other sites More sharing options...
Imoutgoodbye Posted August 9, 2011 Report Share Posted August 9, 2011 I'm not sure where it all leads in FL... but if you have 5 6-sided dice, you can have a maximum roll of 30 and a minimum roll of 5. So, where you're at on damage fluctuates with the roll of the dice or each time the mud checks the weapons damage. Damage roll figures into that somewhere....so does a check for enhanced damage if you have it...I don't get into the whole code side of it. I just want to play. Link to comment Share on other sites More sharing options...
Croyvern Posted August 9, 2011 Report Share Posted August 9, 2011 That's all fine and dandy' date=' by what does that mean in ok? Does that mean each hit will take away an avg of 27hp? I've never played D&D or anything like that so I'm just trying to figure out what's going on here.[/quote'] Modified my Enhanced Damage, Dam Roll, Enemies Armor, and many other special things Link to comment Share on other sites More sharing options...
L-A Posted August 11, 2011 Report Share Posted August 11, 2011 That's all fine and dandy' date=' by what does that mean in ok? Does that mean each hit will take away an avg of 27hp? I've never played D&D or anything like that so I'm just trying to figure out what's going on here.[/quote'] Using the example of 9d5 - or 9 die 5-sided - you take a swipe at me with your broadsword. Assuming you hit me you then get to roll a 5 sided dice 9 times to determine the base damage. The maximum you could achieve is 45 (5 rolls of 9). The minimum you could achieve is 9 (5 rolls of 1). Chances are you will achieve something in between these maximum and minimum values. The 'average' is refering to the value that will be achieved most times. After this other factors (in no particular order) such as resistance, sanctuary enhanced damage, proficiency (to name only a few) are applied to determine the actual damage dealt. This all gives rise to the debate on whether you and a 50d1 vs 1d50 (as a very simplified example) weapon and in what situation. A thief on backstab might decide to go with a weapon capable of an insanely high roll looking for an instant kill. A warrior vs a mage may want to get more constant damage output on all shots. L-A Link to comment Share on other sites More sharing options...
Twinblades713 Posted August 11, 2011 Report Share Posted August 11, 2011 L-A, you had the first part right of the 9d5. Then you contradict yourself. You would roll a 5 sided dice 9 times. Max is 45- 9 rolls of 5. Mjn is 9- 9 rolls of 1 We agree, it was just backwards. I don't get how 50d1 and 1d50 is a debate. 50d1 gives you one possibility. Since the die you are rolling is one sided [a sphere ] it will always land on one. You will always get a score of 50 on an attack of 50d1. 1d50 however is one roll of one die with 50 sides, creating the possibility of a result from 1-50. I'd rather just have the 50, assuming I want the highest roll possible. Link to comment Share on other sites More sharing options...
L-A Posted August 11, 2011 Report Share Posted August 11, 2011 L-A, you had the first part right of the 9d5. Then you contradict yourself. You would roll a 5 sided dice 9 times. Max is 45- 9 rolls of 5. Mjn is 9- 9 rolls of 1 We agree, it was just backwards. I don't get how 50d1 and 1d50 is a debate. 50d1 gives you one possibility. Since the die you are rolling is one sided [a sphere ] it will always land on one. You will always get a score of 50 on an attack of 50d1. 1d50 however is one roll of one die with 50 sides, creating the possibility of a result from 1-50. I'd rather just have the 50, assuming I want the highest roll possible. 1d50 vs 50d1 is a extreme example more to draw attention to how the system works. 1d25 vs 50d1 might be a better example of average roll vs high roll. L-A Link to comment Share on other sites More sharing options...
samag08 Posted August 11, 2011 Report Share Posted August 11, 2011 Good to see you L-A, hope you have been well! Link to comment Share on other sites More sharing options...
H&R Posted August 11, 2011 Report Share Posted August 11, 2011 Twin, the way your calced works too. It's just that 54 / 2 is 27, not 26 Link to comment Share on other sites More sharing options...
Twinblades713 Posted August 11, 2011 Report Share Posted August 11, 2011 It's just that I'm unable to do simple math, but can understand these conceptual rolling patterns. :3 Link to comment Share on other sites More sharing options...
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