Bar Trivia

[Khran]

I'm normally good at these things, but tonight I just couldn't see this one. What do you all think it is and what is your logic behind your answer?

What would the next number sequence be?

* 1

* 11

* 21

* 1211

* 111221

* 312211

* 13112211

* 1113212221

* 311312113211

*

[BobcatFan]

easy 132113111221131221 I think that is right

[spiegel06]

132113111221131221

I think this is it but I might be wrong, a bit tired at the moment,

[spiegel06]

damn you bobcat you beat me to the punch....

[BobcatFan]

I'm normally good at these things, but tonight I just couldn't see this one. What do you all think it is and what is your logic behind your answer?

What would the next number sequence be?

* 1

* 11

* 21

* 1211

* 111221

* 312211

* 1312211---

* 1113212221

* 311312113211

*

you messed up on the 7th line i think

[Khran]

Yea, well I figured it out now.

***** SPOILER *****

1 (next line is exactly the same thing, sort of...you have ONE one)

11 (next line same thing....two one)

21 (next line one two and one one)

1211 (next line the same thing, one one and one two and two one)

111221

312211

13112211

1113212221

311312113211

[Khran]

Or if you want to solve it the easy way....

#include

#include

unsigned nextnum(unsigned k)

{

unsigned breakout[10];

unsigned i;

for(i=0; i < 10; i++)

breakout=0;

while(k > 0)

{

breakout[k%10]++;

k /= 10;

}

for(i=9; i > 0; i--)

if (breakout>0)

k = k*100 + 10*breakout + i;

return k;

}

int main(int argc, char** argv)

{

unsigned x = 1;

unsigned i;

unsigned max = argc > 1 ? atoi(argv[1]) : 14;

printf("iteration %2i: %8i\n", 0, x);

for(i=1; i < max; i++)

{

x = nextnum(x);

printf("iteration %2i: %8i\n", i, x);

}

return 0;

}

[Fiere]

That way does not look easy to me at all.